X^2-7x+10=(x-2)(x+5)

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Solution for X^2-7x+10=(x-2)(x+5) equation: 



X^2-7X+10=(X-2)(X+5)

We move all terms to the left:

X^2-7X+10-((X-2)(X+5))=0

We multiply parentheses ..

X^2-((+X^2+5X-2X-10))-7X+10=0



We calculate terms in parentheses: -((+X^2+5X-2X-10)), so:

(+X^2+5X-2X-10)

We get rid of parentheses

X^2+5X-2X-10

We add all the numbers together, and all the variables

X^2+3X-10

Back to the equation:

-(X^2+3X-10)



We add all the numbers together, and all the variables

X^2-7X-(X^2+3X-10)+10=0

We get rid of parentheses

X^2-X^2-7X-3X+10+10=0

We add all the numbers together, and all the variables

-10X+20=0

We move all terms containing X to the left, all other terms to the right

-10X=-20

X=-20/-10

X=+2

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